<?xml version="1.0" encoding="utf-8"?>
<rss xmlns:atom="http://www.w3.org/2005/Atom" version="2.0"><channel><title>Disqus - Latest Comments for jerry101988</title><link>http://disqus.com/by/jerry101988/</link><description></description><atom:link href="http://disqus.com/jerry101988/comments.rss" rel="self"></atom:link><language>en</language><lastBuildDate>Tue, 29 Jul 2008 16:33:59 -0000</lastBuildDate><item><title>Re: random gubbins</title><link>http://hannahcooper.tumblr.com/post/42933042#comment-1040350</link><description>&lt;p&gt;Hmm. Seems I had misread. &amp;gt;.&amp;lt;&lt;/p&gt;&lt;p&gt;Though.... the fact that the four empty chambers are consecutive doesn't seem (to me) like it would really matter. You can apply the same logic to the situation before finding an empty chamber. I dunno. I'm having a difficult time putting my thoughts to words -- it still just seems that you have better odds re-spinning because you then have 4 possibilities to 'miss' instead of only 3.&lt;/p&gt;</description><dc:creator xmlns:dc="http://purl.org/dc/elements/1.1/">jerry101988</dc:creator><pubDate>Tue, 29 Jul 2008 16:33:59 -0000</pubDate></item><item><title>Re: random gubbins</title><link>http://hannahcooper.tumblr.com/post/42822886#comment-1025782</link><description>&lt;p&gt;Well.... I am no master of probability -- in my opinion, things basically all boil down to 50/50. However, it seems that in this case, if one empty chamber was already found, there is a 1/5 chance you will 'lose', vs a 1/6 chance if you spin again. Therefore spinning again gives you greater odds of 'winning', or staying alive. If your intent was to die, then I suppose you lost.&lt;/p&gt;&lt;p&gt;Either way, I do not plan on playing Russian roulette.&lt;/p&gt;</description><dc:creator xmlns:dc="http://purl.org/dc/elements/1.1/">jerry101988</dc:creator><pubDate>Mon, 28 Jul 2008 20:54:16 -0000</pubDate></item></channel></rss>